f(x)=alltermsf
.0
and 0
into the Answer boxes.
0 < x <
0
Differentiating, we obtain:
f'(x)=alltermsfpr=factoredfpr
Factor f'(x)
, if possible.
The factorization is given by f'(x)=3*p(x+2*a)(x-2*b)
.
Using this factorization,
figure out where
the derivative f'(x)
is positive and negative.
Notice that f'(x)
is negative when x
is a large positive number.
Work along the number line from right to left.
The derivative f'(x)
is
negative on xmax < x
,
positive on xmin < x < xmax
and
negative on x < xmin
.
Then the function f(x)
is
decreasing on xmax < x
,
increasing on xmin < x < xmax
and
decreasing on x < xmin
.
The maximal intervals of decrease are: (xmax < x)
and (x < xmin)
.
They are both unbounded, so, following the directions in the problem,
enter 0
and 0
into the Answer boxes,
to indicate that every maximal interval of decrease is unbounded.
NOTE: The next two hints show: the graph of f
, followed by the graph of f'
.
Note that the graph of f
decreases along unbounded intervals.
Note that the graph of f'
is is below the x
-axis on unbounded intervals.
initAutoscaledGraph( [ xrange , yrange ], {} ); style({ stroke: "#6495ED", strokeWidth: 3 }, function() { plot( function( x ) { return p*x*x*x+q*x*x+r*x+s; }, [-10,10] ); });
initAutoscaledGraph( [ [ -10, 10] , [ -500, 500] ], {} ); style({ stroke: "#6495ED", strokeWidth: 3 }, function() { plot( function( x ) { return 3*p*x*x+2*q*x+r; }, [-10,10] ); });