Prepared: Thu Apr 22 15:37:50 CDT 1999

MATH 1151

Quiz III

1) Solve the following equations:
a) tex2html_wrap_inline16
The equivalent expression in exponential form is

displaymath85

Multiply both sides by 10 and then take cube root to get

eqnarray12

b) tex2html_wrap_inline87

eqnarray17

Here use the property that logarithm is a one-to-one function.

eqnarray25

But if we pick up tex2html_wrap_inline89 , then tex2html_wrap_inline91 will not be defined. So the only solution is tex2html_wrap_inline93 .

2) Use the properties of the logarithm to expand

displaymath95

eqnarray48

3) a) Express in exponential form:

displaymath97

displaymath99

b) Express in logarithmic form:

displaymath101

displaymath103

Note: These convertions should be obvious. But if you are still having trouble, you might want to try the following trick:
Base of logarithm becomes base in the exponent and vice versa. So, for example in the first equation, 7, the base of the logarithm, becomes the base for the exponent.

But this is not all. For the rest, the only thing you need to make sure that the exponential form should look different than the logarithmic form. So it is NOT tex2html_wrap_inline105 but rather tex2html_wrap_inline107 which is obviously different than the logarithmic form. Try this method for different equations.

4) Is it better to invest at 8% compounded quarterly or 7.75% compounded continuously?

The investment formula for interest compounded n times with annual interest rate r is

displaymath109

So $100 in the first plan will become

displaymath111

after one year.

When an interest is compounded continuously, we use the growth function model to find the balance with interest rate r.

displaymath113

So $100 in the second plan will become

displaymath115

after one year.

Obviously the first plan is better since the balance is larger.



Quiz 2 Quiz 4