Prepared : Wed Oct 20 21:56:35 CDT 1999

MATH 1271

QUIZ IV

1) Three large squares of tin, each with edges 1 m long, have four small, equal squares cut from their corners. All twelve resulting small squares are to be the same size (Figure below). The three large cross-shaped pieces are then folded and welded to make boxes with no tops, and the twelve small squares are used to make two small cubes. How should this be done to maximize the total volume of all five boxes?

figure9

Each of the boxes with no tops will have

displaymath92

The small cubes will be made from the small cut parts, hence their volume will be (each)

displaymath94

There are three open boxes and two cubes, hence the total volume is

displaymath96

To find the critical points, first differentiate tex2html_wrap_inline98 with respect to x.

displaymath100

The derivative is zero when

displaymath102

There are also endpoints which have to be considered. In our case the endpoints will be 0 and 1/2, since x denotes a length (which is not negative) and 2x tex2html_wrap_inline104 1.

Plug all the critical points and the endpoints into tex2html_wrap_inline106 and see that when x=1/2 we have the greatest tex2html_wrap_inline106 .

2) A hiker starting at a point P on a straight road wants to reach a forest cabin that is 2 km from a point Q 3 km down the road from P (Figure below). She can walk 8 km/h along the road but only 3 km/h through the forest. She wants to minimize the time required to reach the cabin. How far down the road should she walk before setting off through the forest straight for the cabin? (Suggestion: Use the angle tex2html_wrap_inline110 as the independent variable.)

figure34

The total time spent will be the sum of the time spent on the road and the time spent in the forest. We can express these quantities in pseudo-math as follows:

eqnarray37

The hint in the problem tells us to use tex2html_wrap_inline110 as the variable. Call the amount walked in the forest by y, and the amount walked on the road by x. Then

displaymath114

which gives that tex2html_wrap_inline116 .

Similarly we get that

displaymath118

so tex2html_wrap_inline120 .

Now we can change from the pseudo-math to real math in our first formula.

displaymath122

Differentiate Time with respect to tex2html_wrap_inline110 .

eqnarray54

The critical point will be when

displaymath128

that is when

displaymath130

But actually the problem is not asking for tex2html_wrap_inline110 , rather we are asked to find x.

displaymath136



Quiz 3 Quiz 5