The relationship between determinants and area or volume

From the properties of the cross product and the scalar triple product, we can discover a link between 2 × 2 determinants and area, and a link between 3 × 3 determinants and volume.

2 × 2 determinants and area

Recall that the area of the parallelogram spanned by a and b is the magnitude of a ×b. We can write the cross product of a = a1i + a2j + a3k and b = b1i + b2j + b3k as the determinant

a ×b = i j ka 1a2a3 b1b2b3 .

Now, imagine that a and b lie in the plane so that a3 = b3 = 0. Using our rules for calculating determinants, we see that, in this case, the cross product simplifies to

a ×b = a1a2 b1 b2 k.

Hence, the area of the parallelogram, ||a ×b||, is the absolute value of the determinant

a1a2 b1 b2 .

As mentioned in our discussion about determinant notation, it’s difficult to represent the absolute value of a determinant using the above notation. Instead, we write that the area of the parallelogram spanned by a = a1i + a2j and b = b1i + b2j is

||a ×b|| = det a1a2 b1 b2 .

3 × 3 determinants and volume

The volume of a parallelepiped spanned by the vectors a, b and c is the absolute value of the scalar triple product (a ×b) c. We can write the scalar triple product of a = a1i + a2j + a3k, b = b1i + b2j + b3k, and c = c1i + c2j + c3k as the determinant

(a ×b) c = a1a2a3 b1 b2b3 c1 c2c3 .

Hence, the volume of the parallelepiped spanned by a, b, and c is

|(a ×b) c| = det a1a2a3 b1 b2b3 c1 c2c3 .