Tangent line to parametrized curve examples

Example 1

Given the path (parametrized curve) c(t) = (3t + 2, t2 -7, t - t2), find a parametrization of the line tangent to c(t) at the point c(1).

Solution: The line must pass through the point c(1) = (5, - 6, 0).

The derivative of the path is

c'(t) = 3i +2tj + (1 - 2t)k    

When t = 1, the tangent vector must be

c'(1) = 3i +2j - k.    

A parametrization for the tangent line is

l(t) = c(1) + (t - 1)c'(t0)    
  = (5i -6j) + (t - 1)(3i +2j - k)    
  = (3t + 2)i + (2t - 8)j + (- t + 1)k    

Example 2

Suppose a particle is following the path c(t) = (3t + 2, t2 -7, t - t2). At time t0 = 1, the particle flies off on a tangent. Compute the position of the particle at time t1 = 2.

Solution: The key observation is that, after the time t0, the position of the particle is given by tangent line l(t). From the solution to Example 1, we know that

l(t) = (3t + 2, 2t - 8, - t + 1).    

The particle's position at time t1 = 2 is

l(2) = (8, - 4, 1).    



Duane Nykamp
nykamp@math.umn.edu
2006-10-03