Math 8203
Fall 1997
Comments about Exercise 8
- One reasonably effective way to accomplish the change of variables is the following:
t1 =
x1
+ a1
xn,
t2 =
x2
+ a2
xn,...,
tn-1 =
x2
+ an-1
xn ;
tn
= an xn ,
where a1,...,
an
are elements of K, with
an
0.
The coefficient of
tnd
will then be:
Fd
(a1,...,
an).
Since K is infinite, we can find a point
[a1,...,
an-]
Pn-1
where Fd
(a1,...,
an)
is nonzero. Since K is algebraically closed, we can rescale the
coefficients in this change of variables to make the coefficient of
tnd
be equal to 1.
- Suppose that we have changed variables so that
f(x1,...,
xn)
is monic with respect to
xn,
and let P =
(a1,...,
an-1)
An-1.
Then the polynomial:
g(x) =
f(a1,...,
an-1,x)
has degree = d because of the fact that f is monic with respect to
xn. Therefore
g(x) has d roots, if they are counted with suitable
multiplicities. It follows that at least one point (and at most d points)
of X are mapped to P by the linear projection
:
An ->
An-1.
- This is similar to part (b) of Exercise 7.
- This is similar to part (c) of Exercise 7. In particular, use the hint
which is linked to that exercise. Note that if we're willing to use
the Nullstellensatz, then this problem becomes considerably easier. Indeed,
by applying the Nullstellensatz, we see that I(X) is the principal
ideal (f), which is a prime ideal because the polynomial ring is factorial and
f is an irreducible element. Without the Nullstellensatz, it is not hard to prove this claim directly, but we must say something,
for instance along the lines of the previously mentioned hint.
REMARK.
Let
: X ->
An-1
be induced by the projection
:
An ->
An-1.
The proof of part b shows that
is surjective and also finite to one. Indeed, there are at most d
points of X which map to each point P
An-1.
Since the points of
An-1.
depend in an obvious way on n-1 independent parameters, it makes sense to
say that An-1.
has dimension = n-1. Since
is surjective and finite-to-one, this indicates that it could also make sense to say that the
hypersurface X
has
dimension = n-1.
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