Math 8205
Spring 1998
Assigned exercises
Last updated Thursday, June 18, 1998.
Contents
The first exercise provides an alternate proof of the claim on p.
40 of the text, specifically that if U is a locally closed subset
of An, then the image of
U under the linear projection of An
to An-1 contains a dense
open subset of its image. We start by considering the case where U
is closed in An.
In the second exercise, we will apply this result to prove that the
image of any regular map contains a dense open subset of its closure. So,
in some sense, this is a review exercise.
Exercise 1 (Due Friday,
April 24)
-
Let X
An be a closed subvariety,
and let
: An
-> An- 1 be the linear projection.
Thus,
corresponds to
the inclusion of K[x1,...,xn-1]
in K[x1,..., xn].
Let Y be the closure of
(X)
in An- 1. Show that Y
is the zeroset of the ideal I(X)
K[x1,..., xn-1].
A
solution is linked here.
-
Let g1, ..., gr
be a set of generators of I(X)
K[x1,...,xn-1].
Show that either:
-
I(X) is generated by g1, ..., gr
(considered as elements of K[x1,...,
xn]), or
-
If f
I(X)
is an element of minimal positive xn-degree,
written in the following form:
f(x1,..., xn)
= h0 + h1
xn + ... + hd
xnd,
where h0, ..., hd
K[x1, ..., xn-1]
and hd
0,
then the extension of I(X) to K[x1,...,
xn] [1/hd],
i.e.,
I(X)· K[x1,...,
xn] [1/hd],
is generated by g1, ..., gr
and f.
A
solution is linked here.
-
With the same notation as before, show that either:
-
(X) is closed in An-1,
and X
(X)
A1, or
-
If U = D(hd)
An, then U
Y
(X),
and the restriction of
to
-1
(U
Y)
X
is finite-to-one and surjective (onto U
Y).
A
solution is linked here.
-
Let U
An be a locally closed subset,
and let
: An
-> An- 1 be the linear projection.
Show that
(U)
contains a dense open subset of its closure in An- 1.
A
hint is linked here.
A
somewhat different hint is linked here.
A
solution is linked here.
Exercise 2 (Due Friday, April
24)
-
Let m
n,
and let X
An be a closed subvariety.
Show that if
: An
-> Am is a linear projection,
then
(X) contains
a dense open subset of its closure.
Hint. Proceed by induction on the difference n - m.
A
more detailed hint is linked here.
A
solution is linked here.
-
Show that if X is an affine variety, and
:
X -> An is a regular
map, then
(X)
contains a dense open subset of its closure.
A
solution is linked here.
-
Show that if X is a quasi-projective variety, and
:
X -> Pn is a regular
map, then
(X)
contains a dense open subset of its closure.
A
solution is linked here.
Exercise 3 (Due Thursday,
June 11 ) Let Q
P5 be a smooth quadric
hypersurface: more specifically, Q = G(1,3),
the Grassmannian of lines in P3.
Recall from last quarter that every line on Q is of the form
L =
p,H,
where p is a point in P3
and H is a plane in P3.
Let W be the universal hyperplane in
P3
(P3)*.
Thus, W is the set of all pairs (p,L)
such that p
L. Finally, let F1(Q)
G(1,5) be the Fano variety of lines in Q.
-
Show that there is a regular map
:
W -> G(1,5) whose image is F1(Q).
A
solution is linked here.
-
Show that F1(Q)
is irreducible, and determine its dimension.
A
solution is linked here.
Exercise 4 (Due Thursday,
June 11 ) This problem is about the secant variety of the Veronese
n-fold X = v2(Pn)
PN, where n
2, and N = (n+1)(n+2)/2 - 1 = n(n+3)/2.
(The exact value of N isn't particularly important here,
however.) Recall from the lecture that the secant deficiency
satisfies
1, so that dim(Sec X)
2n. Specifically, every general point of Sec X
lies on (at least) every line in some 1-parameter family of secant lines
of X. We proved that fact by observing that if
L is a line in Pn,
then C := v2(L)
is a curve of degree 2 in some plane
PN. Thus, v2(Pn)
= v2(L), and each point of
lies on every secant line of C in some family parametrized
by P1, and hence on
every line in a 1-parameter family of secant lines of X.
This is illustrated in the following figure. (See pp. 144-145
of the text for the case n = 2.)
In this exercise, our goal will be to show that the inequality
1 is in fact an equality.
-
Assume that n
3, let p,q,r,s be 4 non-coplanar points of
Pn, and consider the
lines L1: = <p,q>
and L2: = <r,s>.
Thus, L1 and
L2 are skew lines. Let
1
and
2
be the planes that contain the curves C1
:= v2(L1)
and C2 := v2(L2)
respectively. Show that
1
2
is empty.
-
Let L1 and
L2 be distinct coplanar lines
in Pn,
and let
1
and
2
be defined as in part a. Show that
1
2
is a single point of X = v2(Pn).
-
Let z be a point of Sec(X) - X.
Show that the set of secant lines passing through z
is irreducible and 1-dimensional.
-
Show that dim (Sec X ) = 2n.
Exercise 5 (Due Thursday,
June 11 ) Let A
B be an integral ring extension.
-
Assume that B is an integral domain. Show that
A is a field if and only if B is a field.
-
Let P be a prime ideal in B,
and let p = P
A.
Show that p is a maximal ideal in A
if and only if P is a maximal ideal in
B.
-
Let S be a subset of A which is closed
under multiplication, and let S-1A
be the ring whose elements are all quotients f/s, where
f
A and
s
S. (As
usual, two quotients f/s and g/t,
are equal if and only if ft - gs is anninilated by some
element of S.) We define S-1B
similarly.
Show that S-1A
S-1B is an integral
ring extension.
-
Let p be a prime ideal in A,
and let S = A - p. Show that if P
is a prime ideal in B which is maximal with respect
to the property that P
S
is empty, then the extended ideal Pe
= P· S-1B
is a maximal ideal in S-1B.
-
Use the result of part d. to prove the existence part of the Lying Over
theorem.
Exercise 6 (Due Thursday,
June 11 ) Let X be a smooth projective variety.
Assume that dim X = r, and that X
P2r + 1.
If L is a line in P2r +1,
and L
X
is empty, then
=
L:
X -> P2r - 1
is the projection whose center is L. Show that if L is a
general line in P2r + 1,
then the following statements hold:
-
there exist at most finitely many points p
X such that (d
)p
: T p(X) -> T
(p)(P2r
- 1) is not injective.
A
solution is linked here.
-
If D = {p
: p
X and
-1(
(p))
contains 2 or more distinct points of X },
then dim(D)
1.
A
hint is linked here.
A
solution is linked here.
REMARK: The meanings of "general"
will be slightly different in part a. and part b. Thus, the lines which
satisfy the each of two conditions correspond to points of two different
dense open subsets of the Grassmann variety G(1,2r + 1).
Of course, the lines which satisfy both conditions correspond to points
in the intersection of the two open subsets.
Comments and inquiries to: roberts@math.umn.edu
Back to my homepage: http://www.math.umn.edu/~roberts